Use this ... output.add("1 2 3 4 5 6 7 8 9 10"); String bigger[] = output.get(i).split(" "); int biggerWher = Arrays.asList(bigger). ... <看更多>

To find the position of an element in an array, you use the indexOf() method. This method returns the index of the first occurrence the element that you want to ... ... <看更多>

尋找是否有符合的元素. 方法一： indexOf. 使用原生JavaScript 的 Array.prototype.indexOf() 。 如下例，陣列fruit 中 ... ... <看更多>

The 'indexOf' array method returns the index position of the array where the supplied value is found. If ... ... <看更多>

var stringArray = java.lang.reflect.Array.newInstance(java.lang.String, 5); stringArray[0] = "a"; stringArray[1] = "b"; stringArray. ... <看更多>

Hmm, interesting. I think I would opt for a two-pass approach: First, join all the strings together and check if your pattern exists in the data at all. ... <看更多>