I believe you can do it like this. String arr[3]; arr[0] = "one"; arr[1] = "two"; arr[2] = "three";. If the array needs to grow in number of ... ... <看更多>

2 Answers · Don't use String . · Use char * and slice the string in-place. · Pass a pointer to an array of pointers and fill that with pointers to the portions of ... ... <看更多>

you just need to instantiate an array that will hold all the chars of the string. * I've put a 100 value for excess, but if you exactly know how many bytes ... ... <看更多>

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