【教學影片】提要022:認識重疊原理( Superposition Principle )▕ 授課老師:中華大學土木系呂志宗特聘教授(加字幕). 1.4K views · 7 years ago ... <看更多>
superposition principle定義 在 Coherence and superposition principle - equivalent ... 的推薦與評價
This makes the definition of "coherence" much harder, as it's not really possible to talk about interference of probability distributions. ... <看更多>
superposition principle定義 在 Re: [理工] [應數] 重疊原理(superposition principle) - 批踢踢實業坊 的推薦與評價
※ 引述《wil0829ly (凱)》之銘言:
: Is the Principle of Superposition even valid for nonhomogeneous
: system of equations? Explain.
: 原題目連結 https://ppt.cc/9iz2 第3題的b
: 請問這題要怎麼證明呢....
: 麻煩版上高手幫個忙
: 謝謝!!
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考慮 X'(t) = A(t)X(t) + b(t)
=> L{X(t)} ≡ X'(t) - A(t)X(t) = b(t)
所以驗證一下當 L{X1(t)} = b1(t)
L{X2(t)} = b2(t)
L{α*X1(t) + β*X2(t)} 是否也會等於 α*b1(t) + β*b2(t)
這應該是不證自明 XD , 答案為 true
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※ 發信站: 批踢踢實業坊(ptt.cc)
◆ From: 140.113.211.139
一般微分方程課本會把線性 ode分成齊性和非齊性的 case
其中齊性 ode 的疊加原理是:
if x1(t) and x2(t) are the sol.s of L{x(t)} = 0
then α*x1(t) + β*x2(t) is also the sol.s of L{x(t)} = 0
而非齊性 ode 的疊加原理是:
given L{x(t)} = b(t), then we can find L{x1(t)}=b1(t) and L{x2(t)}=b2(t)
s.t. L{α*x1(t)+β*x2(t)} = α*b1(t) + β*b2(t)
= b(t)
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若你想寫課本之外的 knowledge 或 concept 當然可以
反正只要批改教授覺得 ok 就好吧
※ 編輯: doom8199 來自: 140.113.211.139 (03/01 14:06)
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